- #1

- 753

- 2

x' = x cos(theta) - y sin(theta)

y' = x sin(theta) + y cos(theta)

One solves for x and y and computes based on the deviation of the deviation.

My question is: would the answer differ if you choose a different point say:

x' = x cos(theta) + y sin(theta)

y' = - x sin(theta) + y cos(theta)

note the negative sign.